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5m^2+3m=54
We move all terms to the left:
5m^2+3m-(54)=0
a = 5; b = 3; c = -54;
Δ = b2-4ac
Δ = 32-4·5·(-54)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-33}{2*5}=\frac{-36}{10} =-3+3/5 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+33}{2*5}=\frac{30}{10} =3 $
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